wait i think i got it... the maximum speed he can be going and stop in time is 19.84 m/s or 71.4 km/h
try that i misunderstood the first time lol
using
d = (v)(t) + (1/2)(a)(t)^2
thats how i came up with my number . . .
v = 88 km/h = 24.4 m/s reaction = 0.75s distance before brakes = d = (24.4 m/s)(0.75)s d = 18.3m to hit brakes total 38.0m - 18.3m leaves 19.7m to stop
t = sqrt (d)(2)/(a) t = sqrt (19.7)(2)/(10) t = 1.98s to stop in time
maximum Velocity he can go using d = (v)(t) + (1/2)(a)(t)^2
19.7 = (v)(1.98s)+(0.5)(-10m/s^2)(1.98s)^2
19.7 = 1.98v - 19.602 39.302 = 1.98v v = 19.84 m/s
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1997 Camaro Z28 - 355 LT1, T56, CC503, LTs, ORY, Bald Eagle-back exhaust, !emissions, Lingenfelter CAI, EWP, !CAGS, BMR LCAs, UMI PHB, Koni Str.t/Koni SA, C5 Z06 front / LS1 F-body rear brake swap, factory hurst with short stick
2014 2LT Cruze 2.0 Turbo Diesel
Last edited by FlyingDutchman; 09-13-2009 at 06:46 PM.
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